Verificación de conceptos: desviación estándar

$\Large\text{Desviación estándar} = \sqrt{\dfrac{\sum\limits_{}^{}{{\lvert x-\bar{x}\rvert^2}}}{n}}$start text, D, e, s, v, i, a, c, i, o, with, \', on top, n, space, e, s, t, a, with, \', on top, n, d, a, r, end text, equals, square root of, start fraction, sum, start subscript, end subscript, start superscript, end superscript, open vertical bar, x, minus, x, with, \bar, on top, close vertical bar, squared, divided by, n, end fraction, end square root

$\text{Desviación estándar} = \sqrt{\dfrac{\sum\limits_{}^{}{{\lvert x-\bar{x}\rvert^2}}}{n}}$start text, D, e, s, v, i, a, c, i, o, with, \', on top, n, space, e, s, t, a, with, \', on top, n, d, a, r, end text, equals, square root of, start fraction, sum, start subscript, end subscript, start superscript, end superscript, open vertical bar, x, minus, x, with, \bar, on top, close vertical bar, squared, divided by, n, end fraction, end square root

$\text{Desviación media absoluta} = {\dfrac{\sum\limits_{}^{}{{\lvert x-\bar{x}\rvert}}}{n}}$start text, D, e, s, v, i, a, c, i, o, with, \', on top, n, space, m, e, d, i, a, space, a, b, s, o, l, u, t, a, end text, equals, start fraction, sum, start subscript, end subscript, start superscript, end superscript, open vertical bar, x, minus, x, with, \bar, on top, close vertical bar, divided by, n, end fraction

$\sqrt{\dfrac{\sum\limits_{}^{}{{\lvert x-\bar{x}\rvert^2}}}{n}}$square root of, start fraction, sum, start subscript, end subscript, start superscript, end superscript, open vertical bar, x, minus, x, with, \bar, on top, close vertical bar, squared, divided by, n, end fraction, end square root

$\sqrt{\dfrac{\sum\limits_{}^{}{{( x-\bar{x})^2}}}{n}}$square root of, start fraction, sum, start subscript, end subscript, start superscript, end superscript, left parenthesis, x, minus, x, with, \bar, on top, right parenthesis, squared, divided by, n, end fraction, end square root